12 J work is to be done against an existing electric field to take a charge of 0.01C from A to B. Find the potential difference between B and A:

Explanation

The work done against an electric field is equal to the change in the electric potential energy of the charge. The change in the electric potential energy is also equal to the potential difference between the two points.In this case, the work done is 12 J, and the charge is 0.01 C. The potential difference between B and A is therefore:V_B - V_A = W / q = 12 J / 0.01 C = 1200 VTherefore, the potential difference between B and A is 1200 V.