Two charges are placed at a certain distance. If the magnitude of each charge is doubled of the force will become:
Correct answer: C. 4 times of orignal value
- A. 1/4th of its orignal value
- B. 1/8th of its orignal value
- C. 4 times of orignal value
- D. 8 times of its orignal value
Explanation
The force between two charges is directly proportional to product of magnitude of charges F =Kq1q2/r2 q1'=2q1 q2'=2q2 F' = (2q1)(2q2)/r2 F'= 4q1q2/r2 F'=4F1 So the magnitude of force becomes 4 times of its initial value.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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