Order of ease of halogenation in alkane is________________?
Correct answer: C. F2>Cl2>Br2>I2
- A. I2>Cl2>Br2>F2
- B. F2>Cl2>I2>Br2
- C. F2>Cl2>Br2>I2
- D. Cl2>F2>Br2>I2
Explanation
The ease of halogenation follows F2 > Cl2 > Br2 > I2 because fluorination is extremely rapid and iodination is generally unfavourable, with chlorination and bromination intermediate. Students may choose an order based on halogen atomic mass, but reaction ease depends on bond energies and energetics, not simply mass.
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About Free Radical Substitution
Free radical substitution explains how alkanes react with halogens under ultraviolet light or heat through initiation, propagation and termination steps. The mechanism involves homolytic bond fission and radical intermediates, while product formation depends on the relative stability of radicals and differs from ionic substitution.
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