Order of ease of halogenation in alkane is________________?
Correct answer: C. F2>Cl2>Br2>I2
- A. I2>Cl2>Br2>F2
- B. F2>Cl2>I2>Br2
- C. F2>Cl2>Br2>I2
- D. Cl2>F2>Br2>I2
Explanation
The ease of halogenation follows F2 > Cl2 > Br2 > I2 because fluorination is extremely rapid and iodination is generally unfavourable, with chlorination and bromination intermediate. Students may choose an order based on halogen atomic mass, but reaction ease depends on bond energies and energetics, not simply mass.
Last updated
About Free Radical Substitution
Free radical substitution explains how alkanes react with halogens under ultraviolet light or heat through initiation, propagation and termination steps. The mechanism involves homolytic bond fission and radical intermediates, while product formation depends on the relative stability of radicals and differs from ionic substitution.
Practise Chemistry of Hydrocarbons
1,091 free Chemistry of Hydrocarbons MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
Chlorination of toluene in the presence of sublight produces_________________?
Consider reversibility in free radical substitution reaction of alkane then Kc value is smallest for:
Free radical reactions take place in the presence of _?
Free radical reactions take place in the presence of _.
H2 and Cl2 do not react in the dark, but in the presence of light a vigorous reaction is initiated due to the formation of: