Natural chlorine occurs as a mixture of isotopes if a mixture contains 75% Cl35 and 25% Cl37 what will be its correct atomic weight?
Correct answer: A. 35.50
- A. 35.50
- B. 34.50
- C. 72.00
- D. 70.00
Explanation
The atomic mass of Cl35 is approximately 35.00 atomic mass units (amu), and the atomic mass of Cl37 is approximately 37.00 amu. To find the atomic weight of the mixture which contains 75% Cl35 and 25% Cl37, we can use the formula:Atomic weight = (abundance of Cl35 × atomic mass of Cl35) + (abundance of Cl37× atomic mass of Cl37)Let's calculate: Atomic weight = (0.75 × 35) + (0.25 × 37) = 26.25 + 9.25= 35.50
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Periodic properties arise from electron configuration and effective nuclear charge, producing trends in atomic and ionic radius, ionization energy, electron affinity, electronegativity, metallic character and reactivity. Comparisons run across periods and down groups, with attention to common exceptions. The topic also relates these trends to the behavior of s-block and p-block elements.
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