Natural chlorine occurs as a mixture of isotopes if a mixture contains 75% Cl35 and 25% Cl37 what will be its correct atomic weight?
Correct answer: A. 35.50
- A. 35.50
- B. 34.50
- C. 72.00
- D. 70.00
Explanation
The atomic mass of Cl35 is approximately 35.00 atomic mass units (amu), and the atomic mass of Cl37 is approximately 37.00 amu. To find the atomic weight of the mixture which contains 75% Cl35 and 25% Cl37, we can use the formula:Atomic weight = (abundance of Cl35 × atomic mass of Cl35) + (abundance of Cl37× atomic mass of Cl37)Let's calculate: Atomic weight = (0.75 × 35) + (0.25 × 37) = 26.25 + 9.25= 35.50
This question appeared on the ETEA MDCAT 2010 paper, which you can sit online with every answer explained.
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