In.transistor, the emitter current, is 3.5A and collector current, is 2.35A.What will be the base current?
Correct answer: B. 1.15A
- A. 5.85A
- B. 1.15A
- C. 1.48A
- D. 0.67A
Explanation
IB =IE −IC Where:( IE ) is the emitter current( IC ) is the collector currentGiven that the emitter current ( IE ) is 3.5 A and the collector current ( IC ) is 2.35 A, the base current ( IB ) can be calculated as: IB =3.5A−2.35A =1.15ASo, the base current is 1.15 A.
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A PN junction forms when p type and n type semiconductor regions meet, creating a depletion layer and a potential barrier. The topic covers forward and reverse bias, diode current voltage characteristics, breakdown and rectification, while distinguishing an ordinary junction diode from a transistor formed from multiple junctions.
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