If the momentum of a body decreases by 20% the percentage decrease in K.E will be:

Correct answer: B. 36%

  • A. 44%
  • B. 36%
  • C. 28%
  • D. 20%

Explanation

Momentum p = mvIf momentum is decreased by 20%, the resulting new value is 80% of the original p-p'P - 0.2p = mv - m0.2vP - 0.2p = (m) (v) (0.8)K.E = ½ mv²= ½ m (0.64v²)K.E = 36%

This question appeared on the ETEA MDCAT 2013 paper, which you can sit online with every answer explained.

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Kinetic Energy

Kinetic energy is the energy of motion, given for a nonrelativistic object by K = ½mv², so it depends on mass and the square of speed. Questions connect kinetic energy with work through the work energy theorem, calculate changes in kinetic energy, and distinguish it from momentum and potential energy.

Practise Work and Energy

748 free Work and Energy MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Kinetic Energy questions