Asked in ETEA MDCAT 2012 2012Moderate

A force of 6 N acts horizontally on a stationary mass of 2 kg for 4 s. The kinetic energy in Joule is:

Correct answer: B. 144

  • A. 12
  • B. 144
  • C. 72
  • D. 48

Explanation

To determine the kinetic energy of the mass after 4 seconds, apply Newton's second law. Given that the force (F) is 6 N and the mass (m) is 2 kg, we first find the acceleration (a) using F = ma, resulting in a = 3 m/s².Initially, the object is stationary, so the initial velocity (u) is 0. The final velocity (v) can be calculated using v = u + at, where t is 4 seconds, giving v = 12 m/s.Now, calculate the kinetic energy (KE) using the formula KE = 1/2 mv². Substituting the values, KE = 1/2 × 2 × (12)² = 144 J.The other options are incorrect due to either a miscalculation of velocity or an incorrect application of the kinetic energy formula.

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