A particle of mass m at rest is acted upon by a force P for time t. Its kinetic energy is:
Correct answer: B. (P2 t2)/2m
- A. (P2 t2)/m
- B. (P2 t2)/2m
- C. (P2 t2)/3m
- D. (P2 t2)/4m
Explanation
The kinetic energy of a particle is given by the formula: KE = ½ mv² In this case, the particle is initially at rest, so its initial velocity (vo) is zero. The force (P) acting on the particle for time t will cause it to accelerate. According to Newton's second law, the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). Using this relationship, we can express the acceleration (a) in terms of force (P) and mass (m): P = ma Solving for acceleration: a = P/m Using the kinematic equation: v = vo + at Since the initial velocity is zero: v = at Now, we can substitute the expression for acceleration into the equation for velocity. v = (P/m)t Finally, we can calculate the kinetic energy by using the formula: KE = ½ mv² Putting values in the equation, we get: KE = ½ m ((P/m)t)² = ½ mt² (P²/m²) KE = (P²/t²) / 2m
This question appeared on the UHS MDCAT 2022 paper, which you can sit online with every answer explained.
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Kinetic energy is the energy of motion, given for a nonrelativistic object by K = ½mv², so it depends on mass and the square of speed. Questions connect kinetic energy with work through the work energy theorem, calculate changes in kinetic energy, and distinguish it from momentum and potential energy.
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