If R= Rmax/2, then angle of projection is:
Correct answer: C. 15o
- A. 30o
- B. 60o
- C. 15o
- D. 45o
Explanation
The range of a projectile is given by R = (vi2 sin(2θ))/g. The maximum range (Rmax) occurs at θ = 45o because sin(90o) = 1. For the range to be half of Rmax, we need sin(2θ) = 1/2. This happens when 2θ = 30o, so θ = 15o, making 15o the correct angle for achieving R = Rmax/2.Angles like 30o and 60o provide ranges due to complementary properties but do not specifically result in half of the maximum range. The angle 45o is incorrect as it provides the entire maximum range.
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