A body is thrown horizontally from the top of a tower of height 5m. It touches the ground at a distance of 10 m from the foot of the tower. The initial velocity of the body is: (g=10ms-2)
Correct answer: C. 10ms1
- A. 2.5ms-1
- B. 5ms-1
- C. 10ms1
- D. 20ms-1
Explanation
The body is projected horizontally, meaning the initial vertical velocity is zero. Use the vertical motion equation s = 1/2 gt2 to find the time of descent, where s = 5m and g = 10ms-2. Solving gives t = 1s.Then, apply the horizontal motion equation v = d/t to determine the initial velocity, with d = 10m and t = 1s. Thus, v = 10ms-1, confirming Option C as correct.Options A and B underestimate the velocity due to incorrect time intervals, while Option D overestimates the velocity, given the constraints of distance and time.
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