A body is thrown with a velocity of 9.8m/s making an angle of 30o with the horizontal. It will hit the ground after a time:
Correct answer: A. 1 sec
- A. 1 sec
- B. 2 sec
- C. 3 sec
- D. 1.5 sec
Explanation
Option A is correct. The formula for the time of flight of a projectile launched at an angle θ with an initial velocity vi is given by 2(vi sin θ)/g, where g is the acceleration due to gravity (approximately 9.8 m/s2). Substituting the values provided (vi = 9.8 m/s and θ = 30°), we get: 2 x 9.8 x sin(30°) / 9.8 = 1 second. The other options (B, C, and D) are incorrect because they do not result from this calculation and are not consistent with the physics of projectile motion.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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