If E be the electric intensity of an electrostatic field, then the electrostatics energy density is proportional to:
Correct answer: B. E2
- A. E
- B. E2
- C. 1/E2
- D. E3
Explanation
The correct answer is that the electrostatic energy density is proportional to E2, where E is the electric field intensity. This relationship is derived from the fact that the energy stored in an electrostatic field is proportional to the square of the field intensity. Thus, as the electric field intensity increases, the energy density increases quadratically. This explains why Option B is correct, while Options A, C, and D are incorrect as they do not accurately represent this relationship.
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About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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