A parallel plate capacitor is charged and the charging battery is disconnected. Then a dieletric slab is introduced between the plates, The quantity that remains unchanged is_
Correct answer: D. Charge
- A. Electric field
- B. Capacitance
- C. Energy
- D. Charge
Explanation
Option D is correct as The quantity that remains unchanged when a dielectric slab is introduced between the plates of a charged parallel plate capacitor is the charge on the plates.This is because the charge on the plates is determined by the amount of current that flowed through the capacitor when it was being charged. Once the battery is disconnected, the current stops flowing and the charge on the plates remains constant.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electrostatics questions
Gaussian surface is:
If E be the electric intensity of an electrostatic field, then the electrostatics energy density is proportional to:
A unit positive charge + qo placed anywhere in the vicinity of a positive point charge, experience a repulsive force directed
The work done in placing a charge of 8uC on a condensor of capicity 100 nF is_
The metallic spheres A and B of radii 2m and 4m respectively carry the same charge 4 x 10^8C. If the spheres are connected by a copper wire than :
Let Q denote charge, V denote potential difference, and U denote stored energy, or these quantities, capacitors in parallel must have the same: