Moderate

A parallel plate capacitor is charged and the charging battery is disconnected. Then a dieletric slab is introduced between the plates, The quantity that remains unchanged is_

Correct answer: D. Charge

  • A. Electric field
  • B. Capacitance
  • C. Energy
  • D. Charge

Explanation

Option D is correct as The quantity that remains unchanged when a dielectric slab is introduced between the plates of a charged parallel plate capacitor is the charge on the plates.This is because the charge on the plates is determined by the amount of current that flowed through the capacitor when it was being charged. Once the battery is disconnected, the current stops flowing and the charge on the plates remains constant.

Last updated

About Electrostatics

Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.

Practise Electrostatics

831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Physics questions like this

Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions