If an AC voltage of 100V peak value is applied as input to a half wave rectifier and then a full wave rectifier, the rms values of outputs will be respectively:
Correct answer: C. 50V and 70V
- A. 35V and 35V
- B. 35V and 70V
- C. 50V and 70V
- D. 70V and 140V
Explanation
The RMS value for a half-wave rectifier is calculated as Vrms = Vpeak/2. Given a peak voltage (Vpeak) of 100V, the half-wave rectifier output is Vrms = 100V/2 = 50V.For a full-wave rectifier, the RMS value is calculated as Vrms = Vpeak/√2. Therefore, the full-wave rectifier output is Vrms = 100V/√2 ≈ 70.7V, which rounds to 70V for simplicity.Therefore, the correct RMS outputs for the half-wave and full-wave rectifiers are 50V and 70V respectively. The other options do not apply the correct RMS formulas for rectifiers.
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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