If an AC voltage of 100V peak value is applied as input to a half wave rectifier and then a full wave rectifier, the rms values of outputs will be respectively:

Correct answer: C. 50V and 70V

  • A. 35V and 35V
  • B. 35V and 70V
  • C. 50V and 70V
  • D. 70V and 140V

Explanation

The RMS value for a half-wave rectifier is calculated as Vrms = Vpeak/2. Given a peak voltage (Vpeak) of 100V, the half-wave rectifier output is Vrms = 100V/2 = 50V.For a full-wave rectifier, the RMS value is calculated as Vrms = Vpeak/√2. Therefore, the full-wave rectifier output is Vrms = 100V/√2 ≈ 70.7V, which rounds to 70V for simplicity.Therefore, the correct RMS outputs for the half-wave and full-wave rectifiers are 50V and 70V respectively. The other options do not apply the correct RMS formulas for rectifiers.

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Electronics

A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.

Practise Electronics

660 free Electronics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Electronics questions