If AC voltage of 60Hz is applied as input to a full wave rectifier, the frequency of output voltage (ripple) will be:
Correct answer: C. 120 Hz
- A. 30 Hz
- B. 60 Hz
- C. 120 Hz
- D. 60/2π Hz
Explanation
A full wave rectifier converts the entire AC waveform to a pulsating DC, effectively doubling the frequency of the input signal. When the input AC frequency is 60 Hz, the output frequency is doubled to 120 Hz, making Option C the correct answer. Option A suggests a frequency reduction, which does not occur in full wave rectification. Option B corresponds to a half wave rectifier scenario, and Option D introduces a mathematical expression that is irrelevant to this context.
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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