A series combination of a 100Ω resistor and an ordinary silicon diode is connected to a 10V battery. The current flowing through the circuit will be:
Correct answer: B. 0.093 A
- A. 0.1 A
- B. 0.093 A
- C. 10.75 A
- D. Zero
Explanation
The circuit consists of a 100Ω resistor and a silicon diode in series with a 10V battery. A silicon diode typically has a forward voltage drop of approximately 0.7 volts when conducting. This means the effective voltage across the resistor is reduced by this diode drop. The total voltage across the resistor is 10V - 0.7V = 9.3V. Using Ohm's Law (I = V/R), where V is the voltage across the resistor and R is the resistance, the current I is calculated as:I = 9.3V / 100Ω = 0.093A or 93mA.This is why the correct answer is 0.093 A. The other options are incorrect because they either ignore the diode's forward voltage drop or suggest unrealistic current values for the given circuit.
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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