Four identical glasses are shown below. One glass is empty, and the other 3 glasses are ¼ full,1/2 full, and ⅘ full of water, respectively. If the water were redistributed equally among the 4 glasses, what fractional part of each glass would be filled?
Correct answer: E. 31/80
- A. 2/11
- B. 8/11
- C. 3/22
- D. 31/60
- E. 31/80
Explanation
To solve the problem, first calculate the total amount of water in the three filled glasses: ¼, ½, and ⅘. Convert these fractions to a common denominator (20) to make calculation easier: ¼ = 5/20, ½ = 10/20, ⅘ = 16/20. Adding these gives you a total of 5/20 + 10/20 + 16/20 = 31/20. Since there are 4 glasses, divide the total water, 31/20, by 4 to find the amount of water per glass: (31/20) ÷ 4 = 31/80. Therefore, each glass would be filled to 31/80 of its capacity when the water is redistributed equally. Options A, B, C, and D do not match this calculation and are therefore incorrect.
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