On the first 7 statistics tests of the semester, Jamal scored 61, 76, 79, 80, 80, 84, and 91. The mean, median, and mode of his scores were 79, 80, and 80, respectively. On the 8th statistics test, Jamal scored 90. How do the mean, median, and mode of all 8 of his scores compare to the mean, median, and mode of his first 7 scores?
Correct answer: E. E
- A. A
- B. B
- C. C
- D. D
- E. E
Explanation
The total 8 test scores arranged in ascending order are:61, 76, 79,80, 80, 84, 90, 91The mode of these is 80 the number that appears the most, same as the mode for the previous 7 scores. Hence mode is equalMedian can term is calculated using the formula (n + 1)/2 where n is the number of terms 8(8+1) / 2 = 4.5th term is the medianTo find the 4.5th term we will find the mean of the 4th and 5th term. So, they are 80 and 80 and their mean will also be 80.Hence, the median is 80 and is equal.For mean, we will divide the sum of the terms by the number of the terms.So, the sum will be 61+76+79+80+80+84+90+91 = 641mean = 641/8 = 80.125 which is greater than the previous mean 79. So, the mean is greater.Hence,Mean = GreaterMedian= EqualMode = Equal
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