Force experienced by a moving change in a magnetic field is:
Correct answer: C. F = q (v x B)
- A. F = BA cosϴ
- B. F = μo NI
- C. F = q (v x B)
- D. F = I (L x B)
Explanation
Explanation:For a charge moving in a magnetic field the force is directly proportional to the charge, velocity of the charge carrier and magnetic field Intensity. As a result, the magnitude of the force is: F = q (v × B) This option is not correct. This is the expression for the force on a current carrying wire in a magnetic field, where B is the magnetic field, A is the area of the loop, and θ is the angle between B and A. This option is also incorrect because this is the expression for the force on a wire carrying a current in a magnetic field, where μo is the permeability of free space, N is the number of turns in the wire, and I is the current. This option is also incorrect because this is the expression for the force on a current carrying wire in a magnetic field, where I is the current in the wire, L is the length of the wire, and B is the magnetic field.
This question appeared on the UHS MDCAT 2009 paper, which you can sit online with every answer explained.
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About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
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