A charge of two microcoulombs (2 μC) moves with velocity of two meter per second (2 m/sec) in the direction of two Tesla magnetic field. The force that will act on it will be:
Correct answer: B. Zero
- A. 2 N
- B. Zero
- C. 8 N
- D. 4 N
Explanation
Explanation:The force experienced by a charge moving in a magnetic field is given by the formula: F = qvBsinθWhere q is the charge, v is the velocity of the charge, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field direction. In this case, the charge is moving parallel to the magnetic field direction (i.e., θ = 0), so the force experienced by the charge will be zero.
This question appeared on the UHS MDCAT 2009 paper, which you can sit online with every answer explained.
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About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
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