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Electrolytic reduction of alumina to aluminium by Hall−Heroult process is carried out:

Correct answer: C. In the presence of cryolite which forms a melt with lower melting temperature.

  • A. In the presence of NaCl.
  • B. In the presence of fluorite.
  • C. In the presence of cryolite which forms a melt with lower melting temperature.
  • D. In the presence of cryolite which forms a melt with higher melting temperature.

Explanation

Option C is correct. The electrolytic reduction of alumina to aluminum by the Hall-Heroult process is indeed carried out in the presence of cryolite. Cryolite lowers the melting temperature of the mixture, enabling the process to be conducted at a lower temperature and thus more energy-efficient. Options A, B, and D are incorrect as they mention NaCl, fluorite, and a higher melting temperature of the melt, respectively, which do not align with the actual process.

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About s-Block and p-Block Elements

The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.

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