Electrolysis of dilute H₂SO₄ liberates which gases at the anode and cathode, respectively?
Correct answer: C. O₂ & H₂
- A. O₂ & SO₂
- B. SO₂ & O₂
- C. O₂ & H₂
- D. H₂ & O₂
Explanation
In the electrolysis of dilute aqueous solutions, water is often oxidized or reduced in preference to the solute ions. At the cathode (reduction). 2H₂O + 2e⁻ → H₂(g)+ 2OH⁻. At the anode (oxidation). 2H₂O → O₂(g) + 4H⁺ + 4e⁻. So, O₂ is produced at the anode and H₂ at the cathode.
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