At 25ºC, the standard emf of a cell having a reaction involving a two-electron change is found to be 0.295 V. The equilibrium constant of the reaction is:
Correct answer: C. 10¹⁰
- A. 29.5 x 10⁻²
- B. 10
- C. 10¹⁰
- D. 29.5 x 10¹⁰
Explanation
The relationship is ΔG° = nFE°_cell = -RTlnK. This simplifies to logK = nE°/0.0592. Plugging in the values, logK = (2 × 0.295. / 0.0592 = 10. Therefore, the equilibrium constant K = 10¹⁰.
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