BeCl2 + LiAlH4 → X + LiCl + AlCl3
Correct answer: B. X is BeH2
- A. X is lithium hydride (LiH)
- B. X is BeH2
- C. X is beryllium dichloride dihydrate (BeCl2 · 2H2O)
- D. X is beryllium hydride (BeH2)
Explanation
In the given chemical equation, BeCl2 reacts with LiAlH4 to produce 2BeH2, LiCl, and AlCl3. Therefore, the correct identity of X is BeH2. Option A, C, and D are incorrect because they do not align with the products formed in the reaction.
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About s-Block and p-Block Elements
The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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