At constant temperature, when the pressure of gas is increased three times then its volume becomes:
Correct answer: C. V/3
- A. 2V/3
- B. 3V
- C. V/3
- D. 5V
Explanation
When the pressure of a gas is increased three times at constant temperature, according to Boyle's Law, the volume of the gas decreases to one-third of its initial volume. Mathematically, this can be expressed as: P1 * V1 = P2 * V2 Where, P1 is the initial pressure V1 is the initial volume P2 is the final pressure (which is three times P1 in this case) V2 is the final volume So, if the pressure is increased three times (P2 = 3P1) and the temperature is constant, the final volume (V2) will be one-third (1/3) of the initial volume (V1).
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About Boyle's Law
Boyle's law states that the pressure of a fixed mass of gas varies inversely with its volume when temperature remains constant. Problems use the relationship P₁V₁ = P₂V₂, pressure-volume graphs and volume changes, with constant temperature distinguishing it from Charles's law.
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