At a constant temperature what should be the percentage increase in pressure for a 5% decrease in the volume of gas:
Correct answer: C. 5.26%
- A. 5%
- B. 10%
- C. 5.26%
- D. 4.26%
Explanation
Solution of the question: P1 V1 = P2 V2 ....(eq1) V2 = 5% decrease in the original volume ∴ V2 = 95 / 100 V1 Put this in eqn 1: P1 V1 = P2 (95 / 100 V1) V1 cancel out on both sides, so we're left with the eqn: P1 = 95 / 100 P2 Making P2 the subject of the formula: P2 = 100 / 95 P1 increase in pressure: P2 - P1 => (100 / 95 - 1) P1 = 5 / 95 P1 = 0.0526 P1 find out % increase by: 0.0526 P1 / P1 x 100 = 5.26%
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About Boyle's Law
Boyle's law states that the pressure of a fixed mass of gas varies inversely with its volume when temperature remains constant. Problems use the relationship P₁V₁ = P₂V₂, pressure-volume graphs and volume changes, with constant temperature distinguishing it from Charles's law.
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