Aspartame, an artificial sweetener contains 9.52 weight per nitrogen. There are two nitrogen atoms per molecule. The molecular weight of aspartame is:
Correct answer: B. 294
- A. 147
- B. 294
- C. 588
- D. 266
Explanation
To find the molecular weight of aspartame, we need to use the information given about the weight percentage of nitrogen and the number of nitrogen atoms per molecule.Let's break it down step by step:1. Weight percentage of nitrogen = 9.52%2. Number of nitrogen atoms per molecule = 23. Atomic weight of nitrogen = 14 g/mol (approximately)Since there are two nitrogen atoms per molecule, the total weight of nitrogen per molecule is:2 x 14 g/mol = 28 g/molNow, we can use the weight percentage of nitrogen to find the molecular weight of aspartame:Weight percentage of nitrogen = (Weight of nitrogen / Molecular weight) x 100Rearranging the equation to solve for molecular weight, we get:Molecular weight = Weight of nitrogen / (Weight percentage of nitrogen / 100)Substituting the values, we get:Molecular weight = 28 g/mol / (9.52 / 100)Molecular weight = 28 g/mol / 0.0952Molecular weight = 294.5 g/molTherefore, the molecular weight of aspartame is approximately 294.5 g/mol, but the closest answer is 294 g/mol.Answer: 294 g/mol.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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