Aspartame, an artificial sweetener contains 9.52 weight per nitrogen. There are two nitrogen atoms per molecule. The molecular weight of aspartame is:
Correct answer: B. 294
- A. 147
- B. 294
- C. 588
- D. 266
Explanation
To find the molecular weight of aspartame, we need to use the information given about the weight percentage of nitrogen and the number of nitrogen atoms per molecule.Let's break it down step by step:1. Weight percentage of nitrogen = 9.52%2. Number of nitrogen atoms per molecule = 23. Atomic weight of nitrogen = 14 g/mol (approximately)Since there are two nitrogen atoms per molecule, the total weight of nitrogen per molecule is:2 x 14 g/mol = 28 g/molNow, we can use the weight percentage of nitrogen to find the molecular weight of aspartame:Weight percentage of nitrogen = (Weight of nitrogen / Molecular weight) x 100Rearranging the equation to solve for molecular weight, we get:Molecular weight = Weight of nitrogen / (Weight percentage of nitrogen / 100)Substituting the values, we get:Molecular weight = 28 g/mol / (9.52 / 100)Molecular weight = 28 g/mol / 0.0952Molecular weight = 294.5 g/molTherefore, the molecular weight of aspartame is approximately 294.5 g/mol, but the closest answer is 294 g/mol.Answer: 294 g/mol.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
Practise Fundamental Concepts of Chemistry
894 free Fundamental Concepts of Chemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Fundamental Concepts of Chemistry questions
3.0 mole of Calcium will contain _ g of Calcium.
Calculate the mass in grams of 8.694 moles of Ag2CO3.
According to Avogadro's law, 0.899g of 1dm3 H2 and 1.4384g of 1dm3 O2 have _number of molecules.
The rate of diffusion of a gas having a molar mass of 32 as compared to H2 gas will be:
Hydrogen peroxide decomposes into oxygen and water. What mass of hydrogen peroxide is required to produce 1L of oxygen?
One mole of substance at STP has: