Hydrogen peroxide decomposes into oxygen and water. What mass of hydrogen peroxide is required to produce 1L of oxygen?
Correct answer: D. 3 g
- A. 1.5 g
- B. 1 g
- C. 2 g
- D. 3 g
Explanation
H2O2 decomposes into O2 and H2O by the following reaction: 22.4 dm3 of O2 = 1 mole of O2 1 dm3 of O2 = 1/22.4 moles of O2 According to the equation; Production of 1 mole of O2 requires 2 moles of H2O2. So 1/22.4 moles of O2 require = (2/22.4) = 1/11.2 moles of H2O2 1 mole of H2O2 = 34 g 1/11.2 moles of H2O2 = 34/11.2 g = 3g Thus 3g of H2O2 must be decomposed to produce 1 dm3 or 1 L of O2.
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