The rate of diffusion of a gas having a molar mass of 32 as compared to H2 gas will be:

Explanation

The rate of diffusion of a gas is inversely proportional to the square root of its molar mass. This relationship is given by Graham's law of diffusion.Graham's law of diffusion is expressed as:Rate₁ / Rate₂ = √(Molar Mass₂ / Molar Mass₁)where:Rate₁ and Rate₂ are the rates of diffusion of gases 1 and 2, respectively.Molar Mass₁ and Molar Mass₂ are the molar masses of gases 1 and 2, respectively.Given that the molar mass of H2 gas is 2 g/mol (since hydrogen has an atomic mass of approximately 1 g/mol), and the molar mass of the other gas is 32 g/mol, we can calculate the ratio of their diffusion rates:Rate₁ / Rate₂ = √(32 gmol- / 2 gmol-)Rate₁ / Rate₂ = √(16)Rate₁ / Rate₂ = 4So, the rate of diffusion of the gas with a molar mass of 32 g/mol will be 4 times slower than the rate of diffusion of H2 gas.