An RL low-pass filter consists of a 5.6 mH coil and a 3.3 kΩ resistor. The output voltage is taken across the resistor. The circuit's critical frequency is______________?
Correct answer: A. 93.8 kHz
- A. 93.8 kHz
- B. 93.8 Hz
- C. 861 Hz
- D. 86.12 kHz
Explanation
For an RL low-pass filter with output across R, the critical frequency is fc = R/(2πL). Using 3.3 kΩ and 5.6 mH gives approximately 93.8 kHz.
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