A series resonant band-pass filter consists of a 2 mH coil, a 0.005 µF capacitor, and a 120 Ω resistor. The winding resistance of the coil is 12 Ω. The output voltage is taken off the resistor. Input voltage is 12 Vrms. What is the output voltage magnitude at the center frequency (f0)?
Correct answer: A. 10.9 V
- A. 10.9 V
- B. 1.09 V
- C. 1.1 V
- D. 12 V
Explanation
At resonance, the inductive and capacitive reactances cancel, so only the resistances remain: 120 + 12 = 132 Ω. The circuit current is 12/132 A, giving the resistor voltage 120(12/132) ≈ 10.9 V.
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