A parallel resonant band-pass filter consists of a 6.8 Ω resistor in series with a parallel network made up of an 8 µH coil and a 120 pF capacitor. The output is taken across the capacitor/coil. Assume RW = 0 Ω. What is the center frequency of the filter?
Correct answer: A. 5.14 MHz
- A. 5.14 MHz
- B. 514 kHz
- C. 5.03 MHz
- D. 503 kHz
Explanation
The resonant frequency is f0 = 1/(2π√LC). Substituting L = 8 µH and C = 120 pF gives approximately 5.14 MHz; the series resistance changes the response but not this ideal center-frequency calculation.
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