An atomic solid has a hexagonal arrangement of unit cells with a height of the hexagonal (in close close-packed arrangement) as "h". The radius of an atom in terms of height is:
Correct answer: D. r=3h/4
- A. r=h/3.266h
- B. r=h/2
- C. r=h/1.633
- D. r=3h/4
Explanation
r=h/3.266 - CorrectThis matches the derived relationship from the ideal hcp ratio, where c/a=1.633 and a=2ra = 2rHence, h=c=1.633×a=3.266r so r=h/3.266
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