A train travels on a straight track passing signal A at 20 m/s. It accelerates uniformly at 2 m/s^2 and reaches signal B 100m further than A. At B the velocity of the train in m/s is
Correct answer: C. 28
- A. 10
- B. 20
- C. 28
- D. 56
Explanation
Using the equation of motion:v² = u² + 2aswhere:v = final velocity (at signal B)u = initial velocity (at signal A) = 20 m/sa = acceleration = 2 m/s²s = distance between signals A and B = 100 mSubstituting the values, we get:v² = (20)² + 2(2)(100)v² = 400 + 400v² = 800v = √800v ≈ 28.28 m/sRounding to the nearest whole number, the velocity at signal B is approximately 28 m/s
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