A handball is tossed vertically upward with a velocity of 19.6 m/s. approximately how high will it rise?
Correct answer: A. 19.6 m
- A. 19.6 m
- B. 39.2 m
- C. 9.8 m
- D. 7.84 m
Explanation
This is the correct answer. We can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity (0 m/s at the maximum height), u is the initial velocity (19.6 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and s is the displacement (maximum height). Plugging in these values and solving for s gives us 19.6 m.
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About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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