A cyclist moving towards right with an acceleration of 4m/ Sec2 at t = 0, he as traveled 5m moving towards the right at 15m/Sec. what be his position at t=2 seconds?
Correct answer: D. 43 meters
- A. 38 meters
- B. 50 meters
- C. 25 meters
- D. 43 meters
Explanation
To find the position of the cyclist at t=2t = 2t=2 seconds, we can use the equations of motion for uniformly accelerated linear motion. Here's how to approach the problem: The cyclist's position at t=2t is 43 meters,
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