A shot leaves a gun at the rate of 160m/s. Calculate the greatest distance to which it could be projected and the height to which it would rise? (g=10m/s2).
Correct answer: B. 2560m, 640m
- A. 1560m, 540m
- B. 2560m, 640m
- C. 3560m. 740m
- D. 4560m, 840m
- E. 9595m, 348m
Explanation
R= u²sin2θ/gFor maximum range θ=45So 160²/10= 2650This alone is sufficient to enable us to narrow our answer to just B (do not waste time finding height while attempting the actual exam!)For height, H= u²sin²θ/2gat θ=45 H=u²/4g160²/4*10=640Which again confirms option B to be correct.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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