Moderate

A rescue helicopter drops a package of emergency ration to a stranded party on the ground. If the helicopter is traveling at 40 m/s at a height of 100 m above the ground, where does the package strike the ground relative to the point at which it was released? (g= 9.8 m/s2)

Correct answer: D. 180.7 m

  • A. 120 m
  • B. 130 m
  • C. 140 m
  • D. 180.7 m
  • E. 200.3 m

Explanation

(Following is the solution to the given problem.)According to the equation of motion: s= ut + ½ at2 Since the initial velocity would be zero S = ½ gt2 100= ½ (9.8) t2 t2= 100 x 2/9.8T2= 100/4.9T2= 20.4T= 4.5 According to the formula s= vt S=40 x 4.5 S= 180.7 m

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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.

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