A rescue helicopter drops a package of emergency ration to a stranded party on the ground. If the helicopter is traveling at 40 m/s at a height of 100 m above the ground, where does the package strike the ground relative to the point at which it was released? (g= 9.8 m/s2)
Correct answer: D. 180.7 m
- A. 120 m
- B. 130 m
- C. 140 m
- D. 180.7 m
- E. 200.3 m
Explanation
(Following is the solution to the given problem.)According to the equation of motion: s= ut + ½ at2 Since the initial velocity would be zero S = ½ gt2 100= ½ (9.8) t2 t2= 100 x 2/9.8T2= 100/4.9T2= 20.4T= 4.5 According to the formula s= vt S=40 x 4.5 S= 180.7 m
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