A player throws a ball at an initial velocity of 36 m/second. The maximum distance the ball can reach (assume the ball is caught at the same height at which it was released) is:
Correct answer: C. 132 m
- A. 146 m
- B. 130 m
- C. 132 m
- D. 129 m
- E. 145 m
Explanation
The maximum range of a projectile is achieved when it is launched at an angle of 45 degrees to the horizontal. The formula for the range is given by R = u2 sin(2θ) / g, where u is the initial velocity and g is the acceleration due to gravity (approximately 9.8 m/s²).For this problem, the initial velocity u is 36 m/s, and the angle θ is 45 degrees. Plugging these values into the formula gives:R = (36)2 sin(90°) / 9.8 = 1296 / 9.8 ≈ 132.2 mThis confirms that the correct answer is approximately 132 m, making Option C the right choice. Other options either overestimate or underestimate the range due to incorrect calculations or assumptions.
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