A mechanic repairs 2 bikes per hour. During an event, he works 3 hours longer than usual. If he fixes 20 bikes, what was his regular working time?
Correct answer: C. 7 hrs
- A. 5 hrs
- B. 6 hrs
- C. 7 hrs
- D. 8 hrs
Explanation
The mechanic repairs 2 bikes per hour. Let 'x' be his regular hours. In those hours, he repairs 2x bikes. During the event, he works an extra 3 hours, repairing 2(x + 3) bikes in total. According to the problem, he fixes 20 bikes: 2x + 6 = 20. Solving for 'x', we find 2x = 14, so x = 7. Therefore, the mechanic's regular working time is 7 hours. Option A (5 hours) results in a total of 16 bikes, which is insufficient. Option B (6 hours) results in 18 bikes, which is still insufficient. Option D (8 hours) results in 22 bikes, which is too many.
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