A javelin is thrown by Arshad Nadeem at a projection angle of 45 degrees with an initial velocity of 30 m/s, the range of the javelin will be: (Consider g = 10 m/s²):
Correct answer: B. 90m
- A. 85m
- B. 90m
- C. 95m
- D. 100m
Explanation
Correct. Here's the calculation:Range formula for projectile motion:Range (R) = (v₀² * sin(2θ)) / gWhere:v₀ = initial velocity (30 m/s)θ = projection angle (45 degrees)g = acceleration due to gravity (10 m/s²)Calculate sin(2θ):sin(2 * 45°) = sin(90°) = 1Calculate the range:R = (30² * 1) / 10 = 900 / 10 = 90 m
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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