A 4 kg body is thrown vertically upward from the ground with a velocity of 5 ms−1. Its kinetic energy just before hitting the ground is
Correct answer: B. 50 J
- A. 25 J
- B. 50 J
- C. 75 J
- D. 100 J
Explanation
Correct. The initial kinetic energy is: KE = (1/2)mv² = (1/2)(4 kg)(5 m/s)² = (1/2)(4)(25) = 50 J Due to energy conservation, the kinetic energy just before hitting the ground is the same as the initial kinetic energy.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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