An aeroplane is flying horizontally with a velocity of 10 m/s and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance)
Correct answer: B. 200 m
- A. 100 m
- B. 200 m
- C. 400 m
- D. 2 km
Explanation
200 m: Understanding Projectile Motion:The horizontal velocity of the bomb remains constant (10 m/s).We need to find the time it takes for the bomb to fall 1960 m.Then we use the time to calculate the horizontal distance traveled.Calculations:Using the equation h = (1/2)gt², where h is the height, g is acceleration due to gravity (9.8 m/s²), and t is time:1960 = (1/2) * 9.8 * t²t² = 1960 / 4.9 = 400t = √400 = 20 secondsHorizontal distance (AB) = horizontal velocity * timeAB = 10 m/s * 20 s = 200 m
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