At a stop light, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity, and the car accelerates at 3 m/s². How much time does the car take to catch up to the truck?

Correct answer: C. 10 s

  • A. 5 s
  • B. 15 s
  • C. 10 s
  • D. 20 s

Explanation

Correct. Here's the calculation:Distance traveled by the truck:Distance_truck = velocity_truck * timeDistance_truck = 15t (where t is the time taken)Distance traveled by the car:Distance_car = initial_velocity_car * t + (1/2) * acceleration_car * t²Distance_car = 0 * t + (1/2) * 3 * t²Distance_car = 1.5t²When the car catches up, the distances are equal:Distance_truck = Distance_car15t = 1.5t²Solve for t:1.5t² - 15t = 01.5t(t - 10) = 0t = 0 (initial time) or t = 10 sTherefore the time taken is 10 seconds

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Force and Motion

Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.

Practise Force and Motion

1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Force and Motion questions