A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is:
Correct answer: D. Option D
- A. Option A
- B. Option B
- C. Option C
- D. Option D
Explanation
The total mass of rope and block = m+M and a force P is being applied to it.Since F = maacceleration = F/macceleration = p/(m+M)So, we know the acceleration of the block and that it has mass M the force willF=maF = M x (P/m+M) F = PM/(m+M)As per Newton's third law, the force applied by the rope is equal to the force experienced by the block.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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