A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is:
Correct answer: D. Option D
- A. Option A
- B. Option B
- C. Option C
- D. Option D
Explanation
The total mass of rope and block = m+M and a force P is being applied to it.Since F = maacceleration = F/macceleration = p/(m+M)So, we know the acceleration of the block and that it has mass M the force willF=maF = M x (P/m+M) F = PM/(m+M)As per Newton's third law, the force applied by the rope is equal to the force experienced by the block.
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