A body moving with velocity V can be stopped by a force F in direction of it. The same body moving with velocity 5 V can be stopped by a force 5F in distance equal to:
Correct answer: B. 5X
- A. X
- B. 5X
- C. 10X
- D. X/2
Explanation
Workdone or energy= F x d Also, Energy=½ mv² So equating them together: F x d= ½ mv² d= mv²/ 2F Since m and ½ are constant d ∝ v²/F d=v²/F When velocity 5v and force 5F then d: d'=(5v)²/(5F) d'=25v²/5F= 5v²/F Comparing these two: d'=5d
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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