A 500 turns solenoid develops an average induced voltage of 60 V. Over what time interval must a flux change of 0.06 Wb occur to produce such a voltage ?
Correct answer: C. 0.5 s
- A. 0.01 s
- B. 0.1 s
- C. 0.5 s
- D. 5 s
Explanation
Using e = N(ΔΦ/Δt), the required time is t = NΔΦ/e = 500 × 0.06/60 = 0.5 s. Thus the flux change must occur over half a second.
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