Find the force acting on a conductor 3m long carrying a current of 50 amperes at right angles to a magnetic field having a flux density of 0.67 tesla
Correct answer: A. 100 N
- A. 100 N
- B. 400 N
- C. 600 N
- D. 1000 N
Explanation
For a conductor perpendicular to the field, F = BIl = 0.67 × 50 × 3 = 100.5 N, approximately 100 N. The right-angle condition makes the sine factor equal to one.
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