A conductor carries 125 amperes of current under 60° to a magnetic field of 1.1 tesla. The force on the conductor will be nearly______________?
Correct answer: B. 120 N
- A. 50 N
- B. 120 N
- C. 240 N
- D. 480 N
Explanation
The force is F = BIL sin θ = 1.1 × 125 × sin 60° ≈ 119 N, which rounds to 120 N. The sine factor is needed because the conductor is at 60° to the field.
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