50 cm of KOH solution was titrated against 1.0M HCIusing phenolphthalein as an indicator. The acid used was found to be 7,5 cm. the concentration of KOH solution is:
Correct answer: A. 0.15 M
- A. 0.15 M
- B. 1.5 M
- C. 0.75
- D. None
Explanation
The calculations are shown below : The chemical equation used in this titration is : HCl+KOH→KCl+H₂O In this chemical reaction, the molar ratio between HCl and KOH is 1:1. So, moles of HCl = moles of KOH Mʜᴄʟ × Vʜᴄʟ = Mᴋᴏʜ × Vᴋᴏʜ Mʜᴄʟ × Vʜᴄʟ ----------------- = Mᴋᴏʜ Vᴋᴏʜ (placing values) 1 × 7.5 ------------ = Mᴋᴏʜ 50 Mᴋᴏʜ = 0.15M
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